ELEC 2200 HW11 M11x

ELEC 2200 HW11 M11x - (Y0,Y1,Y2,Y3,Y4,Y5) are to be...

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ELEC 2200 – Homework #11 Due: Wednesday, June 22 1. Write the logic expression corresponding to output Y5 of the 74138 decoder module in Figure 4.8 of the text book, and then use this expression to describe how this decoder operates (how it is enabled, how the output correspond to a minterm when enabled, active-high vs active-low, etc.) 2. Design a logic circuit for a 3-to-6 decoder, using a minimal number of gates. Do not simply use 6 of the 8 outputs of a 3-to-8 decoder - there are “don’t care” terms that should be considered in the decoder design, so the outputs will not necessarily be full minterms. The inputs to be decoded (C,B,A) are active-high, and there is to be one active-low enable signal E. The outputs
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Unformatted text preview: (Y0,Y1,Y2,Y3,Y4,Y5) are to be active-low. 3. Implement the following functions, using a single 3-to-8 decoder module, with active-high outputs, and no more than two additional gates. gGuu GUuuu Guu GuUuu 4. Implement the following functions, using a single 74138 module and no more than two additional gates. gGuu Guuu Guu Guu 5. Implement the MIN function of the last problem of midterm quiz 1 (y 1 y ) using a single 74154 4-to-16 decoder module and two additional gates. The 74154 is shown in Figure 4.9 note that the four inputs DCBA are active-high, and not active low as erroneously pictured in Figure 4.9(d)....
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This note was uploaded on 09/23/2011 for the course ELEC 2200 taught by Professor Singh during the Summer '08 term at Auburn University.

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