problem02_46 solution

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.46: a) The vertical distance from the initial position is given by ; 2 1 2 0 gt t v y y - = solving for v 0 y , . s m 5 . 14 ) s 00 . 5 )( s m 80 . 9 ( 2 1 ) s 00 . 5 ( ) m 0 . 50 ( 2 1 2 0 = + - = + = gt t y v y b) The above result could be used in ( 29 , 2 0 2 0 2 y y g v v y y - - = with v = 0, to solve for y y 0 = 10.7 m (this requires retention of two extra significant figures in the calculation
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Unformatted text preview: for v y ). c) 0 d) 9.8 2 s m , down. e) Assume the top of the building is 50 m above the ground for purposes of graphing:...
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• Initial Position, extra significant figures

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