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Unformatted text preview: f’(x) < 0 on (3,+oo); f’(x) = 0 at x = 3. 4. f’’(x) > 0 on (oo,5), and (1,+oo); f’’(x) < 0 on (5,1); f’’(x) = 0 at x = 1. 16 15 1413 121110 9 8 7 6 5 4 3 2 1 ) 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 X Y 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9...
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This note was uploaded on 09/25/2011 for the course CALCULUS 135 taught by Professor Augustarainsford during the Spring '11 term at Rutgers.
 Spring '11
 Augustarainsford

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