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graphsampleANS - 4 f’’(x> 0 on-oo-5 and-1 oo...

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Draw a graph of a function y = f(x) which satisfies the following conditions: 1. f(x) is continuous and differentiable everywhere except at x = -5. 2. limit f(x) = +oo limit f(x) = -oo limit f(x) = 3 and limit f(x) = -4 x->-5 - x->-5 + x->-oo x->+oo 3. f’(x) > 0 on ( -oo,-5), and (-5,-3) ; f’(x) < 0 on ( - 3,+oo); f’(x) = 0 at x =
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Unformatted text preview: 4. f’’(x) > 0 on (-oo,-5), and (-1,+oo); f’’(x) < 0 on (-5,-1); f’’(x) = 0 at x = -1. -16 -15 -14-13 12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 ) 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 X Y 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9 INCREASING | INC | DECREASING CONCAVE UP | CON DOWN | CONCAVE UP...
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