HLRGAATPreISM_35799X_09_ch9

# HLRGAATPreISM_35799X_09_ch9 - Chapter 9 Trigonometric...

This preview shows pages 1–3. Sign up to view the full content.

Chapter 9: Trigonometric Identities and Equations 9.1: T r igonometr ic Identities 1. Since by the negative-number identities the function is : Odd. 2. Since by the negative-number identities the function is : Even. 3. Since by the negative-number identities the function is : Odd. 4. Since by the negative-number identities the function is : Odd. 5. Since by the negative-number identities the function is : Even. 6. Since by the negative-number identities the function is : Odd. 7. By a quotient identity, therefore B. 8. By a quotient identity, therefore D. 9. By a negative-number identity, , therefore E. 10. By a pythagorean identity, , therefore C. 11. By a pythagorean identity, , therefore A. 12. Using a quotient identity, , therefore C. 13. Using a pythagorean identity and then a quotient identity, therefore A. 14. Using two reciprocal identities and then a quotient identity, therefore E. 15. Using a pythagorean identity, , therefore D. 16. Using a reciprocal identity, therefore B. 17. By a negative-number identity, if . 18. By a negative-number identity, if . 19. By a negative-number identity, if 20. By a negative-number identity, if 21. By a negative-number identity, if 22. By a negative-number identity, if 23. The correct identity is the function must have the argument “ x ” or 24. The square root of a sum does not equal the sum of the square roots: 25. sin in terms of cot sin in terms of sec 2 sec 2 u 1 sec u sin u cos u sin u cos u cos u tan u 1 sec u 1 2 sec 2 u 1 2 u : u sin u 1 csc u 1 2 1 cot 2 u 2 1 cot 2 u 1 cot 2 u u : u 2 a 2 b 2 2 a 2 2 b 2 , so 2 sin 2 u cos 2 u sin u cos u . u , t , etc. 1 cot 2 x csc 2 x ; cot 1 u 2 cot u , then cot a 4 π 7 b cot 4 π 7 . tan 1 u 2 tan u , then tan a π 7 b tan π 7 . sin 1 u 2 sin u , then sin 1 2.5 2 sin 2.5. sin 1 u 2 sin u , then sin 1 .5 2 sin .5. cos 1 u 2 cos u , then cos 1 5.46 2 cos 5.46 cos 1 u 2 cos u , then cos 1 4.38 2 cos 4.38 cos 2 x 1 sec 2 x , 1 sin 2 x 1 csc 2 x cot 2 x 2 sin 2 x sin x cos x tan x , sec x csc x 1 cos x 1 sin x sec 2 x 1 tan 2 x sin 2 x cos 2 x , tan x cos x sin x cos x cos x 1 sin x sin 1 x 2 1 sin 2 x cos 2 x tan 2 x 1 sec 2 x cos 1 x 2 cos x tan x sin x cos x , cos x sin x cot x , csc x csc 1 x 2 , sec x sec 1 x 2 , cot x cot 1 x 2 , tan x tan 1 x 2 , cos x cos 1 x 2 , sin x sin 1 x 2 ,

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
26. cos in terms of sin cos in terms of cot cos in terms of csc 27. tan in terms of sin tan in terms of cos tan in terms of sec tan in terms of csc 28. cot in terms of sin cot in terms of cos cot in terms of csc 29. sec in terms of sin sec in terms of tan sec in terms of cot sec in terms of csc 30. csc in terms of cos csc in terms of tan csc in terms of cot csc in terms of sec 31. 32. 33. sin b tan b cos b sin b cos b tan b tan b tan b tan 2 b cot a sin a cos a sin a sin a 1 cos a tan u cos u sin u cos u cos u 1 sin u csc u 2 tan 2 u 1 tan u sec u 2 sec 2 u 1 sec u 2 sec 2 u 1 sec 2 u 1 u : u csc u 2 1 cot 2 u u : u B tan 2 u 1 tan 2 u 2 tan 2 u 1 tan u B 1 1 tan 2 u csc u 2 1 cot 2 u u : u csc u 1 sin u 1 2 1 cos 2 u 2 1 cos 2 u 1 cos 2 u u : u 2 csc 2 u 2 csc 2 u 1 csc u 2 csc 2 u 1 csc u 2 csc 2 u 1 csc 2 u 1 1 B 1 1 csc 2 u 1 B csc 2 u 1 csc 2 u sec u 1 cos u 1 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern