**Unformatted text preview: **Between t = 5 s and t = 9 s, the area under the trapezoid is (1/2)(45 m/s + 20 m/s)(4 s) = 130 m (compare to Eq. (2.14)), and so the total distance in the first 9 s is 230 m. Between t = 9 s and t = 13 s, the area under the triangle is m 90 s) 4 )( s m 45 )( 2 1 ( = , and so the total distance in the first 13 s is 320 m....

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- Binary relation, Equals sign, Total Distance