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Unformatted text preview: P = 40 watts = V 2 /R eq = 10 2 /(3R/2) and solving for R = 5/3 ohms . The 100 mA is flowing through R 2 and has 5 volts across it. R 2 = 5/.1 =50 ohms . R 2 has 5 volts across it and R 1 has 125 = 7 volts across it. R 1 = 7/.1 = 70 ohms . A 200 ohm resistor is added in parallel with R 2 and has an equivalent resistance of (200)(50)/(200+50) = 40 ohms. The voltage divider equation can be used to find v o = 12(40)/(70+40) = 4.36 volts . HW 2 2 The parallel resistors have an equivalent resistance of (15)(5)/(15+5) = 3.75 ohms. This 3.75 ohms has a current of 10 A flowing through it which makes the voltage across it (10)(3.75)=37.5 volts. Then i 3 = 37.5/5 = 7.5 amps . By inspection, the matrix equation is: 1 = 1/20+1/10 –1/10 v 1 2 = –1/10 1/5+1/10 v 2 1 = .15 –.1 v 1 2 = –.1 .3 v 2 v 1 = 14.29 i 1 =( v 1v 2 )/10 v 2 = 11.43 i 1 = .286 amps...
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This note was uploaded on 09/24/2011 for the course E E 331 taught by Professor Staff during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Staff

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