HW5answers - HW 5 (a) The 1 uf and 2 uf in series on the...

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HW 5 1 (a) The 1 uf and 2 uf in series on the left have a cap of (1)(2)/(1+2) = 2/3. The 2/3 uf in parallel with the 3 uf is (2/3)+3 = 3.6666 uf. Going to the right side of the circuit, the 1 uf and 1 uf in parallel have an equivalent capacitance of 1+1 = 2 uf. The 2 uf in series with the 2 uf on the right has an equivalent capacitance of (2)(2)/(2+2) = 1 uf. The remaining 3.6666 uf and 1 uf are in parallel so their capacitance is the sum or 4.6666 uf. (b) The 2 uf and 1 uf in parallel have 3 uf total. The 4 uf and 2 uf in parallel have 6 uf total. The 6 uf in series with the 3 uf have (6) (3)/(6+3) = 2 uf which is the answer. (a) The 1 h and 3 h are in series so the total for them is 4 h. The 4 h is in parallel with the 2 h so its equivalent inductance is (4)(2)/ (4+2)=8/6 = 1.3333 h. The 1.3333 h is in series with the remaining 1 h inductance so the total is their sum or 2.3333 h . (b) The 2 h and 2 h are in parallel so their equivalent is (2)(2)/(2+2)=1 h. The 2 h and 6 h are in parallel so their equivalent is (2)(6)/
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This note was uploaded on 09/24/2011 for the course E E 331 taught by Professor Staff during the Fall '08 term at University of Texas at Austin.

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HW5answers - HW 5 (a) The 1 uf and 2 uf in series on the...

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