{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# HW5answers - HW 5(a The 1 uf and 2 uf in series on the left...

This preview shows pages 1–2. Sign up to view the full content.

HW 5 1 (a) The 1 uf and 2 uf in series on the left have a cap of (1)(2)/(1+2) = 2/3. The 2/3 uf in parallel with the 3 uf is (2/3)+3 = 3.6666 uf. Going to the right side of the circuit, the 1 uf and 1 uf in parallel have an equivalent capacitance of 1+1 = 2 uf. The 2 uf in series with the 2 uf on the right has an equivalent capacitance of (2)(2)/(2+2) = 1 uf. The remaining 3.6666 uf and 1 uf are in parallel so their capacitance is the sum or 4.6666 uf. (b) The 2 uf and 1 uf in parallel have 3 uf total. The 4 uf and 2 uf in parallel have 6 uf total. The 6 uf in series with the 3 uf have (6) (3)/(6+3) = 2 uf which is the answer. (a) The 1 h and 3 h are in series so the total for them is 4 h. The 4 h is in parallel with the 2 h so its equivalent inductance is (4)(2)/ (4+2)=8/6 = 1.3333 h. The 1.3333 h is in series with the remaining 1 h inductance so the total is their sum or 2.3333 h . (b) The 2 h and 2 h are in parallel so their equivalent is (2)(2)/(2+2)=1 h. The 2 h and 6 h are in parallel so their equivalent is (2)(6)/ (2+6)=12/8 = 1.5 h. The 1.5 h is in series with the 1 h so that inductance is 2.5 h that is to the

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

HW5answers - HW 5(a The 1 uf and 2 uf in series on the left...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online