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278 - ILS~I2 CONT SUBSTU‘UTE‘ NUMERICAL VALUES:nzosen...

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Unformatted text preview: ILS~I2 CONT. SUBSTU‘UTE‘ NUMERICAL VALUES: :nzosen L-asom e=|°0 mm 8 :20 Ht“. 3.;- no mm a. I 15 MM F'axE‘D- F REE COLUMN Etnr"=M a P(e 1- S—N') max/warm”) 421%. M=C.SUN*x+C‘CO$1x1-e+$ nr’=c.-k ceslx ~czAsmix me. N'(o)-o c._= ~c-8 3.6.. ~"(o)=o C. =0 ~'= (c+€)(:-cos.lx) 3.6. N'(L)=5' .1 8:90;: AL-l) 4.— MnM-P(e.+$)= Pc seal; ‘— NOTE: N‘: e.(s¢c-lL)(1-cas 4x) ILS—IO thED- FREE COLUMN S= DEFLECTION hr THE 1'09 us: 512411-513 wzrn L acnncsp av rm: EQUIvaLexr LENGTH 1.1.: S=e(sec Alp-1). e sour: FOR L'- L‘— Aaccos e1: 9 E: L'V'PE' hkccos 27? (:3 sun‘srwu'r: NUHERICOL VhLUl’S: 2:13 GP; #21300 NH t:ann P=so KN 8:30 mm earo rm I“-.:X-*-—-(J-- --.1.f:)4'=l:4>lB4-ulo'b ”14" FROM $111.0): L 22,2; n .— ts—(d:—d‘)-3.ots no" MM." .'. P‘ “$.26 RN 2 Fvlzr '0 0 5.35113 9-2.1 sun-1 so 1': 3%? 7, and - -:—.-(1:.ux~)= 8.2.1 m: d— USE Ea.(n-sc)w1'rn L REPLACED 3v Le=sz MM”:- 9: ssclL A317,??? _ Pu} 5:30 xm’xsl Mn“ .- Pe sec :1: H =‘o pm. Max 5 8x 13‘ ' I; It: +.31w."’ Jr=4.nl MI. 6 =? - 2.086110. 1.: H F'l' a «.3 w! sussfrrwrs uunr‘mcn anuss: 4o x-m. = P(2.oaawgse<: (0.96114?) SOLVE Nunsmcsusr: P-- 6.73 K IIJ-H- .Fxxso-rast caLurm use ta.(n—5(.) szH I. «truce» av Leazu Man=Pe suit. lag _. PI} E=3oxw’ KS! m... - 9° 5“ Vfi' n... ~70 m... 5 no x35: .8- 1125.34 m“ A-amu m. e=?=z.472 m. Luau-ra- m m. SUSSTITUTE NUMERICRL VhLVEs: 7o x-m. = P(2.+‘1‘LIN.)S£‘C-{O.383+V\/?) sour: NUMERIcaLLYr P: “,7 K .- Mk1 FIXEO- FEE E COLUMN 8: DEFLEGT‘ION n1- 1'1-15 for use ‘EQ.(H-$I) wrrH L Kenn-can 91' Tu: EQUIVALENT LENGTH 2.1.:- S=e(s:c4I¢.L-— -—K)l SOLVE F03- L' L 3 '_ ARCCDS j- A! £7? UVM n: Atccos— a?” (1) szsrnrm—z NUMERICAL VALurs1 15:10.0 x 10‘ K3: Amen m. baa: w. 9- 30 K {$2.0 m. e = 3.0114. 1=-.;7.v “1'?“ «233* = {5:111 1...“- FROM 541.0): L...M a130,: n~.= 10.9 Fr.— FlKE‘D‘ FREE“ COLUMN 8: DEFLECTION AT THE TOP us: ea. (11—5-1) wrrH I. REPLACED ay 1-»: EQUIVALENT LENGTH 2L: S=e(sz-:c AL-I) aka-Vé' I =-e(ssc1’n"c‘ n) sows Far. P: n} " e E: : kkccos -—‘-e._ 51‘ e 1 P8 11—(Mzccos 6+5) (1) wale E‘=:omo° rs: 4 L: 20 Era-2+0”:- 1.: «Fra4sm. e-mm. (9 ass“ EQ.(ll-562 J. L , r Mn“ =Pe sac-T i=3]??— 0) ”‘1 PL': an“ a. PC. sac 421‘ NH“ =1 90 K-m. $U§$T|TUTI HUNERICRL VRLUES: 80.000 u-IN. = Patna.) ssc.(o.oovoo9fP") SOLVE NUMERICALLY: 7.? P: 4462. L8 },= & a»! out-HALF?“ Lon» Pa 2111 L3 sussnrurt w £9.03. NM —37. '1 K-m. 3'1.’7Q— 80-0 =3 0.47 ‘— I,_= 1.11m. = 18$ LB/m. = 7.7.30 Ls/r'rq— RATIO I 2.78 ...
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