EOC Chapter 5 - CHAPTER 5 GASES AND THE KINETIC MOLECULAR...

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CHAPTER 5 GASES AND THE KINETIC– MOLECULAR THEORY 5.1 a) The volume of the liquid remains constant, but the volume of the gas increases to the volume of the larger container. b) The volume of the container holding the gas sample increases when heated, but the volume of the container holding the liquid sample remains essentially constant when heated. c) The volume of the liquid remains essentially constant, but the volume of the gas is reduced. 5.2 The particles in a gas are further apart than those are in a liquid. a) The greater empty space between gas molecules allows gases to be more compressible than liquids. b) The greater empty space between gas molecules allows gases to flow with less resistance (hindrance) than liquids. c) The large empty space between gas molecules limits their interaction, allowing all mixtures of gases to be solutions. d) The large empty space between gas molecules increases the volume of the gas, therefore decreasing the density. 5.3 The mercury column in the mercury barometer stays up due to the force exerted by the atmosphere on the mercury in the outer reservoir just balancing the gravitational force on the mercury in the tube. Its height adjusts according to the air pressure on the reservoir. 5.4 On a mountaintop, the air pressure is less, so the height of mercury it balances in the barometer is shorter than at sea level where there is more air pressure. 5.5 The ratio of the heights of columns of mercury and water are inversely proportional to the ratio of the densities of the two liquids. 2 2 HO Hg Hg H O h d hd = 2 2 Hg H g x d hh d = = () 3 2 13.5 g/mL 10 m 1 cm 730 mmHg 1.00 g/mL 1 mm 10 m ⎛⎞ ⎜⎟ ⎝⎠ = 985.5 = 990 cmH 2 O 5.6 P (mmH 2 O) = 2 2 Hg H g x d d = = ( 13.5 g/mL 755 mmHg 1.00 g/mL ) = 10192.5 = 1.02 x 10 4 mmH 2 O 5.7 Plan: Use the conversion factors between pressure units: 1 atm = 760 mmHg = 760 torr = 101.325 kPa = 1.01325 bar Solution: a) 760 mmHg 0.745 atm 1atm = 566.2 = 566 mmHg b) 1.01325 bar 992 torr 760 torr = 1.32256 = 1.32 bar c) 365 kPa 101.325 kPa = 3.60227 = 3.60 atm d) 101.325 kPa 804 mmHg 760 mmHg = 107.191 = 107 kPa 5-1
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5.8 a) () 2 3 10 m 1 mm 1 atm 76.8 cmHg 1cm 760mmHg 10 m ⎛⎞ ⎜⎟ ⎝⎠ = 1.01083 = 1.01 atm b) 101.325 kPa 27.5 atm 1atm = 2.786 x 10 3 = 2.79 x 10 3 kPa c) 1.01325 bar 6.50 atm = 6.5861 = 6.59 bar d) 760 torr 0.937 kPa 101.325 kPa = 7.02808 = 7.03 torr 5.9 a) P (atm) = 2 2.75 x 10 mmHg 760 mmHg = 0.361842 = 0.362 atm b) P (atm) = 86 psi 14.7 psi = 5.85034 = 5.9 atm c) P (atm) = 6 5 9.15 x 10 Pa 1.01325 x 10 Pa = 90.303 = 90.3 atm d) P (atm) = 4 2.54 x 10 torr 760 torr = 33.42105 = 33.4 atm 5.10 a) 1 atm = 1.01325 x 10 5 N/m 2 The force on 1 m 2 of ocean is 1.01325 x 10 5 N. F = m x g 1.01325 x 10 5 N = mg 5 2 kg • m 1.01325 x 10 s = (mass) (9.81 m/s 2 ) mass = 1.03287 x 10 4 = 1.03 x 10 4 kg b) 2 32 4 2 kg 10 g 10 m 1.03287 x 10 1kg m = 1.03287 x 10 3 g/cm 2 (unrounded) H e i g h t = 3 3 2 g1 m L 1 c m 1.03287 x 10 22.6 g 1 mL cm = 45.702 = 45.7 cm Os 5.11 The statement is incomplete with respect to temperature and mass of sample. The correct statement is: At constant temperature and moles of gas, the volume of gas is inversely proportional to the pressure.
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This note was uploaded on 09/25/2011 for the course CHM 2046 taught by Professor Veige/martin during the Spring '07 term at University of Florida.

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EOC Chapter 5 - CHAPTER 5 GASES AND THE KINETIC MOLECULAR...

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