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Unformatted text preview: F 1 sin 40° = 150 sin 40° = +96.4 F 2 F 2 cos 110° = 120 cos 110° = 41.0 F 2 sin 110° = 120 sin 110° = + 112.8 F 3 F 3 cos 160° = 80 cos 160° = 75.2 F 3 sin 160° = 80 sin 160° = + 27.4 F R +114.9 – 41.0 75.2 = 1.3 +96.4+112.8 + 27.4= 236.6 F R =  1.3 x + 236.6 y  F R  = (236.6) 1.3) (2 2 + = 236.6; Direction of F R: tan θ = 236.6/(1.3) ! θ = 89.7° but clearly the resultant vector lies in the second quandrant, so must add 180° ! θ = 89.7° + 180° = 90.3°...
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This note was uploaded on 09/25/2011 for the course PHY 2053 taught by Professor Buchler during the Spring '06 term at University of Florida.
 Spring '06
 Buchler
 Physics, Work

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