Unformatted text preview: moving? m 1 m 2 Solution: Mass 1: T  f = 0 since a = 0 Also, f = µ k m 1 g Combining these gives: T = k m 1 g Mass 2: m 2 g  T = since a = 0 Substituting T = k m 1 g into the equation for mass 2 gives m 2 g  k m 1 g = Solving for k : k = 1 2 m m = 0.33 Note on the hazards of ‘cut and paste’: The problem explicitly (and incorrectly) stated that the table was frictionless, so I also accepted the answer k = 0....
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This note was uploaded on 09/25/2011 for the course PHY 2053 taught by Professor Buchler during the Spring '06 term at University of Florida.
 Spring '06
 Buchler
 Physics, Friction, Mass, Work

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