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Unformatted text preview: 60 6 kg 100 N Solution: Free body diagram: f F v F h mg N a F v = 100 sin 60 = 100 sin 60 F h = 100 cos 60 Vertical: F v = mg + N Solving for N gives N = F v mg Horizontal: F h f = ma but f = k N = k (F v mg) Substituting expressions for F v into equation for f , followed by substitution of f and F v into equation for horizontal motion gives: 100 cos 60  k ( 100 sin 60 mg) = ma Solving for k gives: mg ma k = o o 60 sin 100 60 cos 100 = 0.28...
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 Spring '06
 Buchler
 Physics, Force, Work

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