# 10a - Free body diagram 40° 15.0 kg T F px F py Solution...

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PHY2053 – Section 6168 Quiz #10 Friday, March 26, 2004 Name____________ KEY _____________ UFID___________________ Please read the problem carefully and be sure to show all of your work. Partial credit will be given. A 15.0 kg floodlight is supported at the end of a horizontal beam of negligible mass that is hinged to a pole. A cable at an angle of 40° with the beam helps to support the light. a) Find the tension in the cable. b) the horizontal and vertical forces exerted on the beam by the pole.

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Unformatted text preview: Free body diagram 40° 15.0 kg T F px F py Solution: Let L be the length of the horizontal pole, and T be the tension in the cable a) Compute the torques about the point where the horizontal pole intersects the vertical pole: Ê τ = 0 ! T sin 40° L - m light gL = 0 ! T = m light g/ sin 40° = (15)(9.8)/ sin 40° = 228.7 N b) From Ê F x = 0 ! F px – T cos 40° = 0 ! F px = T cos 40° = 175.2 N From Ê F y = 0 ! F py + T sin 40° - m light g = 0 ! F py = m light g - T sin 40° = 0 N...
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10a - Free body diagram 40° 15.0 kg T F px F py Solution...

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