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Unformatted text preview: Free body diagram 40 15.0 kg T F px F py Solution: Let L be the length of the horizontal pole, and T be the tension in the cable a) Compute the torques about the point where the horizontal pole intersects the vertical pole: = 0 ! T sin 40 L  m light gL = 0 ! T = m light g/ sin 40 = (15)(9.8)/ sin 40 = 228.7 N b) From F x = 0 ! F px T cos 40 = 0 ! F px = T cos 40 = 175.2 N From F y = 0 ! F py + T sin 40  m light g = 0 ! F py = m light g  T sin 40 = 0 N...
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 Spring '06
 Buchler
 Physics, Mass, Work, Light

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