# 11a - Solution First find the moment of inertia for Zorg...

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PHY2053 – Section 7392 Quiz #11 Friday, April 2, 2004 Name_______________________________ UFID___________________ Please read the problem carefully and be sure to show all of your work. Partial credit will be given. The planet Zorg has a radius of 7.1 x 10 8 m and a mass of 5.98 x 10 26 kg. The length of the Zorgian day is 36 hours. Compute the angular momentum of Zorg that arises from it spinning on its axis.
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Unformatted text preview: Solution: First, find the moment of inertia for Zorg about its axis: I Zorg = (2/5)M Zorg R 2 Zorg-Sun = (5.98 x 10 26 )(7.1 x 10 8 ) 2 = 3.01 x 10 44 kg m 2 Next, find the rotational angular velocity: ω Zorg = 2 π /T rotation = 2 π /[(36)(60)(60)] = 4.85 x 10-5 s The angular momentum is: L Zorg = I Zorg ω Zorg = (3.01 x 10 44 kg m 2 )( 4.85 x 10-5 ) = 1.46 10 40 kg m 2 /s...
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