11b - Solution: Treat Morg as a point-like mass orbiting...

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PHY2053 – Section 6168 Quiz #11 Friday, April 2, 2004 Name_______________________________ UFID___________________ Please read the problem carefully and be sure to show all of your work. Partial credit will be given. The planet Morg has a mass of 5.98 x 10 23 kg. The length of the Morgian year is 2.8 earth years and Morg is located a distance of 4.3 x 10 11 m from its sun. Compute the orbital angular momentum of Morg.
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Unformatted text preview: Solution: Treat Morg as a point-like mass orbiting the sun. First, find the moment of inertia: I Morg = M Morg R 2 Morg-Sun = (5.98 x 10 23 )( 4.3 x 10 11 ) 2 = 1.11 x 10 47 kg m 2 Next, find the orbital angular velocity: ω Morg = 2 π /T orbit = 2 π /[(2.8)(365)(24)(60)(60)] = 7.12 x 10-8 s The angular momentum is: L Morg = I Morg ω Morg = (1.11 x 10 47 )( 7.12 x 10-8 ) = 7.89 10 39 kg m 2 /s...
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This note was uploaded on 09/25/2011 for the course PHY 2053 taught by Professor Buchler during the Spring '06 term at University of Florida.

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11b - Solution: Treat Morg as a point-like mass orbiting...

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