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Unformatted text preview: c) What is the limiting velocity v L after the parachute opens? Here we must find the limit as t approaches infinity of the velocity after the parachute opens, so we must set up a new I.V.P. that is: using the integrating factor we solve we also know that when the parachute opens, so so the limiting veocity v L =15ft/s d) Determine how long the sky diver is in the air after the parachute opens. Here we want x(t) again, so we have to integrate our v(t) and x(0) is 0, since we are finding the distance from the point where the parachute opens. and we also know the parachute travels 5000  1074.5 = 3925.5 ft so we set x = 3925.5 ft and solve for t and we find t = 256.6s 25272931...
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 Spring '10
 RamaRao
 Math, Differential Equations, Equations, Prime number, Parachute

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