{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ELEMENTRY DIFFERENTIAL EQUATIONS 2.3

# ELEMENTRY DIFFERENTIAL EQUATIONS 2.3 - c What is the...

This preview shows pages 1–31. Sign up to view the full content.

ELEMENTRY DIFFERENTIAL EQUATIONS CHAPTER 2 2.3 PROBLEMS 1-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
5-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
7-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
9-
13-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
17-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
19-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
21-

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
23- Given: Weight of the diver = 180lb, g 32ft/s (i)--- mg = 180, m = 180/32 (ii)--- x(0) = 5000ft (iii)--- air resistance = 0.75|v| when parachute is closed (iv)--- air resistance = 12|v| when parachute is open (v)--- parachute opens after 10s a) Find the speed of the sky diver when the parachute opens. v(10) must be found and an I.V.P. must be set up for when the sky diver is free falling. The I.V.P. is: we know g, and m, so

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
and v(0) = 0, so and and after 10 seconds when the parachute opens. b) Find the distance fallen before the parachute opens. We know that so we must integrate our equation for v to find x.
distance travelled is then

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: c) What is the limiting velocity v L after the parachute opens? Here we must find the limit as t approaches infinity of the velocity after the parachute opens, so we must set up a new I.V.P. that is: using the integrating factor we solve we also know that when the parachute opens, so so the limiting veocity v L =15ft/s d) Determine how long the sky diver is in the air after the parachute opens. Here we want x(t) again, so we have to integrate our v(t) and x(0) is 0, since we are finding the distance from the point where the parachute opens. and we also know the parachute travels 5000 - 1074.5 = 3925.5 ft so we set x = 3925.5 ft and solve for t and we find t = 256.6s 25-27-29-31-...
View Full Document

{[ snackBarMessage ]}

### Page1 / 31

ELEMENTRY DIFFERENTIAL EQUATIONS 2.3 - c What is the...

This preview shows document pages 1 - 31. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online