Chap.1-intro to electronics-Handout

Chap.1-intro to electronics-Handout - 9/1/2011 Introduction...

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9/1/2011 1 1 Professor: Dr. Chu RyangWie Introduction to Electronics - Read Sections 1.1 through 1.6 1 2 Text book : Microelectronic Circuits, 6 th Ed, by Sedra/Smith (Oxford 2010) Course Grading : 70% Four Examinations ( the lowest score exam is dropped ) 20% Quizzes and Attendance ( 10% of quizzes are dropped ) 10% Pspice Assignments Course Contents (6 th ed. ; 5 th ed. is ok ) : 1. Introduction (Ch1, Ch2) 2. Semiconductors (Ch3) 3. PN Junction Diodes (Ch4) 4. Bipolar Junction Transistors (Ch6) 5. MOS Field-Effect Transistors (Ch5) 6. Building Blocks of IC Amps (Ch7) Goal : Understand physics, operating principles and circuit models of Diodes, MOS and BJT transistors and apply to analysis and design of simple amp ckts. Contact : wie@buffalo.edu , 645-1023 Exam#1 Exam#2 Exam#3 3 Classroom Seating ONE EMPTY SEAT between you and seats on either side. Do: Don’t: Do: Don’t: Seat straight columns ; don’t seat zig-zag pattern
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9/1/2011 2 Channel Setting Instructions for ResponseCard RF 1. Press and release the "GO" button. 2. While the light is flashing red and green, enter the 2 digit channel code. Channel = 10 3. After the second digit is entered, Press and release the "GO" button. 4. Press and release the "1/A" button. The light should flash yellow to confirm. 4 1. Signal Source • A fundamental function of electronic circuits is to process signals. • Signals contain information about a variety of things and activities in our physical world. Example - information about weather: air temperature, humidity, pressure, etc. • To process the information by electronic systems, the signal must first be converted into an electric signal, i.e., a voltage or current , by a device called “ transducer ”. • An electric signal source can be represented by either (a) Thévenin or (b) Norton form: 5 Thevenin form Norton form (a) - Voltage Source: signal as time-varying voltage - Thevenin form - Open-circuit voltage: v OC = v s (t) - Short-circuit current: i SC = v s (t)/R s (b) - Current Source: signal as time-varying Current - Norton form - Open-circuit voltage: v OC = i s (t)R s - Short-circuit current: i SC = i s (t) 1. Signal Source v oc and i sc 6 Thevenin Norton Summary
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9/1/2011 3 Solution) v OC = 10 mV i SC = 10 uA R s = V OC / i SC = 10 mV/ 10 uA = 1k W Voltage (Thevenin) or Current (Norton) source, the solution is the same 7 Ex.1.2) A signal source has an open-circuit voltage of 10 mV and a short-circuit current of 10 uA . What is the source resistance R s ?
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This note was uploaded on 09/25/2011 for the course ECON 101 taught by Professor Wang during the Spring '11 term at SUNY Buffalo.

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Chap.1-intro to electronics-Handout - 9/1/2011 Introduction...

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