Principles of Physics I
PHYS 2211160
Exam #4
Chapter 15 and Thermodynamics
Spring 2010
Name__
Solutions
_______________
You might like to know that 1.00atm = 1.013x10
5
Pa ,
σ
= 5.67x10
8
J/(s m
2
K
4
) , k = 1.38x10
23
J/K , R =
8.31J/(mol K) , N
A
= 6.02x10
23
/mol, the density of copper is 8920kg/m
3
, the thermal conductivity of
copper is 390.J/(s m
o
C) , the specific heat capacity of copper is 387 J/(kg
o
C), the density of gold is
19300kg/m
3
, the density of mercury is 13600kg/m
3
, the specific heat capacity of liquid water is 4186J/(kg
o
C) , the specific heat capacity of ice is 2.00x10
3
J/(kg
o
C), the latent heat of fusion of water is
33.5x10
4
J/kg .
1.
(5 points)
A water pipe has a circular intake opening with a radius of 3.00cm where the water has a speed of
2.00m/s .
What is the speed of the water exiting the pipe where the radius of the pipe is 2.50cm ?
a)
1.39 m/s
b)
1.67 m/s
From the continuity equation we have A
1
v
1
= A
2
v
2
, so
c)
2.00 m/s
d)
2.40 m/s
v
2
= A
1
v
1
/ A
2
=
π
(0.0300m)
2
(2.00m/s) / [
π
(0.0250m)
2
] = 2.88m/s
e)
2.88 m/s
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 Spring '11
 lomant
 Thermodynamics, Fundamental physics concepts

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