This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Ch. 3 Kinematics in 2D Now let’s consider the concepts of displacement , velocity , and acceleration in 2 dimensions. o f x x x = Δ t x x t x v o f = Δ Δ = t v v t v a o f = Δ Δ = 2 2 1 at t v x x o o f + + = a v v x o f 2 2 2 = Δ 1D o f r r r v v v = Δ t r r t r v o f v v v v = Δ Δ = t v v t v a o f v v v v = Δ Δ = 2 2 1 t a t v r r o o f v v v v + + = a v v r o f v v v v 2 2 2 = Δ 2D In general, for 2D, displacements, velocities, and accelerations will have components in both the x and ydirection. Concepts from Ch. 1 Thus, y x r r r v v v + = y x v v v v v v + = y x a a a v v v + = 2 2 1 t a t v x x x o o f x + + = 2 2 1 t a t v y y y o o f y + + = We get 2 equations of motion under constant acceleration – one for the x direction, and one for the ydirection. Example : A car drives 60 o N of E at a constant speed of 35 m/s. How far east has the car traveled after 10 s? E, x N, y v = 35 m/s 60 o We can break the velocity down into its x and ycomponents. v y v x Now I can calculate the values for v x and v y : o x v v 60 cos = o y v v 60 sin = m/s 5 . 17 ) m/s)( 35 ( 2 1 = = m/s 3 . 30 ) m/s)( 35 ( 2 3 = = For distance in the xdirection (east) we use v x : t v x x = Δ m 175 s) m/s)(10 17.5 ( = = 3.3 Projectile Motion Now let’s analyze the motion of projectiles launched into the air, but this time, the motion is not completely vertical – 2D projectile motion....
View
Full
Document
 Spring '08
 BLACKMON
 Physics, Acceleration

Click to edit the document details