problem02_28 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.28: a) Interpolating from the graph: left) the (to s cm 3 . 1 , s 0 . 7 At right) the (to s cm 7 2 s, 0 . 4 At - = + = v . v b) 2 s 0 . 6 s / cm 0 . 8 s cm 3 . 1 graph - of slope - = - = = t v a which is constant c) = x area under v - t graph First 4.5 s: Triangle Rectangle A A x + = ( 29 ( 29 cm 5 . 22 s cm 6 s 5 . 4 2 1 s cm 2 s 5 . 4 = + = From 0 to 7.5 s:
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Unformatted text preview: The distance is the sum of the magnitudes of the areas. ( 29 ( 29 cm 5 . 25 s cm 2 s 5 . 1 2 1 s cm 8 s 6 2 1 = + = d d)...
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This document was uploaded on 02/04/2008.

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