EE567_Fall2009_HW5_Solutions

# EE567_Fall2009_HW5_Solutions - Homework#5 Solutions EE 567...

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Unformatted text preview: Homework #5 Solutions EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 (a) (a) At the output of the receiver, the pdfs will be Gaussian with the means, ‐3Ep, ‐Ep, Ep and 3Ep, respectively, all with variance σ = N/2 Ep. The decision thresholds are at ‐2Eb, 0, and 2Eb. (b) P(e|m‐3) = P(e|m3) = Q( / σ) = Q( P(e|m‐1) = P(e|m1) = 2 × Q( / / σ) = Q( ) = Q( / ) ) = 2 × Q( ) P(e) = P(e) = Where Eb = Ep can be used to find EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 EE 567 Communication Systems Fall 2009 ...
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