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Unformatted text preview: 1 [A] k 1 = 0.025 sec-1 k 2 = 0.010 sec-1 Part B. Assume the first reaction is first order, but the 2 nd reaction is an enzymatic reaction, i.e. r c = Vm*[B]/(Km + [B]) k 1 = 0.25 sec-1 Vm = 0.37 mmol/sec Km = 0.015 mmol You may wish to compare your solution to a simple Euler method to verify behavior....
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- Spring '10