Solutions in bold
Problem 1
An ideal plug flow reactor has a volume of 100 L with a flowrate of 15 L/min and an
initial concentration of 22 mol/L.
The reaction, A > B, has k=4.7 L/molmin.
A.
Calculate the outlet concentration
(mol/L) of reactant from this reactor.
0.0319 mol/L
B.
Alternatively, a larger mixed flow reactor (500 L) is available using the same
processing conditions.
Calculate the outlet reactant concentration
(mol/L) of this
reactor.
0.371 6
mol/L
C.
Calculate the conversion
for each reactor.
Which reactor gives a better
conversion?
Part a. X =
0.998
Part b. X =
0.983
Plug flow reactor gives better conversion.
Problem 2
An enzymatic reaction runs in a series of 2 equal volume mixed flow reactors.
Given the
data below:
A. Derive the expression for the outlet concentration
(C) for a single mixed flow
reactor with an enzymatic reaction occurring as a function of K
m
, V
m
,
τ
m
and Co.
Data:
 V
m
C
r
= 
K
m
+ C
V
m
= 6.3 mol/Lmin K
m
= 3.2 mol/L C
o
= 5.6 mol/L
τ
m
= 15.7 min
C1 = {[ K
m
+
τ
m
V
m
– Co]+SQRT[(K
m
+
τ
m
V
m
– Co)^2 + 4K
m
Co]}/2
B. Calculate the overall conversion
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 Spring '10
 PETERWILAON
 Fluid Dynamics, Enzyme, Inductor, The Conversion, Plug Flow Reactor

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