{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw14_sol - ENGINEERING MECHANICS STATICS 2nd Ed W F RILEY...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ENGINEERING MECHANICS - STATICS, 2nd. Ed. W. F. RILEY AND L. D. STURGES ' 8-12* A bar is loaded and supported as shown in Fig. P8—12. (a) Determine the maximum axial load transmitted by any transverse cross section of the bar. Draw an axial force diagram for the bar. SOLUTION For overall equilibrium of the bar: + T ZFY : R - 2(40) + 2(50) - 2(10) — 10 = 0 R = 10 kN = 10 kN T Fig. P8-12 A load diagram for the bar. free—body diagrams for parts of the bar above sections in intervals AB, BC, and CD of the bar. and an axial force diagram for the bar are shown below. From the free-body diagrams: = --FAB — 10 - 2(10) = 0 FAB = -30 kN i 30 kN (C) —FBC - 10 - 2(10) 2(50) = 0 FBC = 70 kN = :9 kN (Tl -FCD + 10 + 2(10) 2(50) + 2(40) = CD = -10 kN = 10 kN (C) _ _ “*2 BC _ 70 kN - 70 RN (T) _ Ans. ENGINEERING MECHANICS - STATICS, 2nd. Ed. W. F. RILEY AND L. D. STURGES Five GOO-mm diameter pulleys are keyed to a steel shaft as shown in Fig. P8—14. The pulleys carry belts that are used to drive machinery in a factory. Belt tensions for normal operating conditions are indicated on the figure. Determine the maximum torque transmitted by any transverse cross section of the shaft. 1‘ SOLUTION ll A load diagram for the shaft, free-body diagrams for parts of the shaft to the left of sections in intervals AB, BC, CD, and DE of the shaft, and a torque diagram for the shaft are shown below. LooN-m. 720 N-m ll 1 - From the free-body diagrams: l + C ZMX = TAB - 600 = 0 L + C zMx TBC - 600 + 480 = 0 = 120 N-m 120 N'm -C— l ‘ + C XMX TCD — 600 + 480 — 720 = 0 = 840 N-m 840 N;m -C— - 600 + 480 - 720 + 720 = 0 ' 120 N'm = 120 N'm -C- DE TCD = 840 N-m = 340 N'm -C— I Ans. ESGINEERING MECHANICS — STATICS. 2nd. Ed. W. F. RILEY AND L. D. STURGES 8—15* Determine the internal resisting forces and moment transmitted by section aa in the bracket shown in Fig. PH-15. SOLUTION From a free—body diagram for the part of the bracket to the right of section aa: 2F = 300 - P = 0 X P = 300 lb = 300 lb +- = V + 500 = 0 -500 lb 2 500 lb ¢ M + 500{12) - 300(8) = 0 M —3600 in-lb = 3500 in.°lb C ENGINEERING MECHANICS - STATICS, 2nd. Ed. W. F. RILEY AND L. D. STURGES 8-17 Determine the internal resisting forces and moment transmitted by section aa in the curved bar shown in Fig. P8-17. SOLUTION From a free-body diagram for the part of the curved bar to the right of section aa: + x7 ZFX, —P - 750 sin 30° = 0 P -375 lb = 375 1b /” v — 750 cos 30° 0 649.5 lb a 650 lb “\ Ans. M — 750 cos 30° (30 cos 30°) - 750 sin 30° (30 - 30 sin 30°) 22,500 in.-lb = 22.5 in.'kip C 8—36* A beam is loaded and supported as shown in Fig. P8—36. Using the coordinate axes shown, write equations for the shear V and bending moment M for any section of the beam in the interval 0 < x < 6 m. SOLUTION From a free-body diagram for the complete beam: I! Q + C 2MB = 18 - A{8} + 5(6){5} A = 21 kN = 21 kN T - S 6: If\ y interval 0 V a 21 - 5x = —5x + 21 RN —18 + 21x — 5{x1{x/2i z ~2.5x2 + 21x — 18 kN'm '73) ENGINEERING MECHANICS - STATICS, 2nd. Ed. W. F. RILEY AND L. D. STURGES 8-44 A beam is loaded and supported as shown in Fig P8-44. Using the coordinate axes shown. write equations for the shear V and bending moment M for any section of the beam in the interval 0 < x ( 4 m. SOLUTION From a free-body diagram for the complete beam: + C 2MB = 9 - AllO} + 18(6){9} + 36(41 = 0 112.5 kN = 112.5 kN T For the interval 0 < x < 4 m: V = 112.5 - 18(x + 2} = -18x + ?6.5 kN M -9 + 112.5x - 18(x + lex + 2)/2 —9x2 + ?6.5x — 45 kN-m ENGINEERING MECHANICS - STATICS, 2nd. Ed. W. F. RILEY AND L. D. STURGES 8-56* Draw complete shear and moment diagrams for the beam shown in Fig. P8-56. SOLUTION From a free-body diagram for the complete beam: + C EMA = 8(8) — 30(4)(2) — 40(6) = 0 B = 60 kN + c 2MB = -A(8) + 30(4)(6) + 40(2) = A = 100 kN Load, shear, and moment diagrams for the beam are shown below: 40 RM 30 Km»... ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern