Unformatted text preview: 4.10 n. 300 al
nub”)
OJSOIbnqlisOH lb" 4 unknowns (m,,nlz,V,,,m,)
also»... ",0 . 1b,. "‘(lbJ  2 balances
OLOOIan:H,OH . 1b,. 22mm
moon," H20 lb, 0 DP
"u(Bi')
MUN)
0.400lan;H,OH It...
(moon:m ":0 .« n,"
b. 300 a] m’ 0.877x62._4lb.
"" = 7.48059] n’ =_2195lb
W: m. +m2 = m, (I)
W: 0.750»)l +0.400mZ = 0.600m.1 (2)
Solve") & (2) simultaneously 3m. = l6461bm,m, = 3841 lb.
1646Ib14805g_
V‘" g 0.952 x 62 Alb“ m’ ”07‘"
4.12 a.
75: kg/h
1000 _ 1 ,h 0.960kgCH30H/kg 2 unknowns (m,x)
0.500kgCH30H/kg 0040k8H20’ 1‘8 2balances
0.500kgH20/ kg 0 DP
673kg/h
x(kgCH3OH/ kg) 1 x(kg H20/ kg) b. gleaming: 1000=rh+673=>rh=327kglh
Methanol balance: f0500(1 000) = 0.960(327) + x(673) => 1: = 0276 kg CH3OH I kg M 1 ﬂ w
m—olCH OH 673kg 0276mm:n 0H 1—0003
hl 32 OgCH3OH 673kg0.724kgH20 1000g kgmolHZO
h kg kg l8gH20 Mole fraction of Methanol:
530 x103
51~30><103 +2.71x10‘ = 5.80 x 103 molCH3OH / h =2.71x10‘molH20/h = 0.176 molCH3OH/ mol c. Analyzer is wrong, ﬂow rates are wrong, impurities in the feed, a reaction is taking place, the
system is not at steady state. ...
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 Fall '11
 STAFF

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