HW#4 solution - 4.10 n 300 al nub” OJSOIbnqlisOH lb"...

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Unformatted text preview: 4.10 n. 300 al nub”) OJSOIbnqlisOH lb" 4 unknowns (m,,nlz,V,,,m,) also»... ",0 .- 1b,. "-‘(lb-J - 2 balances OLOOIan:H,OH .- 1b,. 22mm moon," H20 lb, 0 DP "u-(Bi') MUN) 0.400lan;H,OH It... (moon:m ":0 .« n," b. 300 a] m’ 0.877x62._4lb. "" = 7.48059] n’ =_2195lb W: m. +m2 = m, (I) W: 0.750»)l +0.400mZ = 0.600m.1 (2) Solve") & (2) simultaneously 3m. = l6461bm,m, = 3841 lb. 1646Ib14805g_ V‘" g 0.952 x 62 Alb“ m’ ”07‘" 4.12 a. 75: kg/h 1000 _ 1 ,h 0.960kgCH30H/kg 2 unknowns (m,x) 0.500kgCH30H/kg 0-040k8H20’ 1‘8 -2balances 0.500kgH20/ kg 0 DP 673kg/h x(kgCH3OH/ kg) 1- x(kg H20/ kg) b. gleaming: 1000=rh+673=>rh=327kglh Methanol balance: f0500(1 000) = 0.960(327) + x(673) => 1: = 0276 kg CH3OH I kg M 1 fl w m—olCH OH 673kg 0276mm:n 0H 1—0003 hl 32 OgCH3OH 673kg|0.724kgH20 1000g kgmolHZO h kg kg l8gH20 Mole fraction of Methanol: 530 x103 51~30><103 +2.71x10‘ = 5.80 x 103 molCH3OH / h =2.71x10‘molH20/h = 0.176 molCH3OH/ mol c. Analyzer is wrong, flow rates are wrong, impurities in the feed, a reaction is taking place, the system is not at steady state. ...
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