Lecture 7 09-07-11

# Lecture 7 09-07-11 - Pressure manometer problems...

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1 Pressure - manometer problems Temperature Scales temperature and temperature interval conversions Extra Credit (5 pts for each event, must sign in) Game Night Thursday Sept. 8 th Willoughby Lounge 6 - 8 pm AICHE Picnic Wednesday Sept. 7 th Reaves Park 6:30 -8:30 pm The pressure exerted by seawater, or by any liquid at rest, is known as hydrostatic pressure . Hydrostatic Pressure depends on two principles depth density fluid fluid h g area force P ρ = gh P P o ρ + = Pressure on leg 1 at (a) = Pressure of leg 2 (b) 1 1 1 2 2 2 P f gd P gd gh ρ + = + + General Manometer Equation P 1 + 1 gd 1 P 2 + 2 gd 2 + f gh Pressure on leg 1 at (a) = Pressure on leg 2 at (b) = the fluid pressure must be the same at any 2 points at the same height in a continuous fluid. Example: Determine the pressure drop across the orifice meter as shown below. l Fluid: water d mm 32 mm 10 ρ 1 = 1000 kg/m 3 ρ f = 1100 kg/m 3 1 1 2 f P gd P gd + = + ( ) 1 2 1 f P P P gd = Δ = Given: l Fluid: water Manometer Fluid mm 32 mm 10 P 1 P 2 Find: the the pressure drop across the orifice Plan: - Perform a force (pressure balance) where the liquid is continuous - use the hydrostatic pressure equation P = ρ gh Solution: P 1 + 1 g ( d + l ) = P 2 + f gd + 1 gl ρ 1 = 1000 kg/m 3 ρ f = 1100 kg/m 3 Fluid: water Manometer Fluid mm 32 mm 10 l ( ) 1 2 1 f P P P gd = Δ = ( )( ) 2 3 2 2 m kg 1 N 9.8 0.022 m 1100 1000 m kg s m 1 s N 21.6 21.6 Pa m P Δ = = = ρ 1

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## This note was uploaded on 09/26/2011 for the course CH E 2033 taught by Professor Staff during the Fall '11 term at The University of Oklahoma.

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Lecture 7 09-07-11 - Pressure manometer problems...

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