Quiz 3 Solution

# Quiz 3 Solution - i.e p(B)=0.35 therefore we have P(A)=0.40...

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1. (2 points) P(tacos or low profit)=p(tacos)+p(low profit)-p(tacos and low profit)=722/4755+1206/4755-238/4755=0.3554 2. (2 points) P(baby burgers|medium)=p(baby burgers and medium)/p(medium)=312/1580=0.1975 3. (2points) Father Burger (1313/4755 is the highest probability) 4~5 (4 points) Since A and B are mutually exclusive, so P(A and B)=0 p(A or B)=p(A)+p(B), i.e., 0.75=0.4+P(B),

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Unformatted text preview: i.e., p(B)=0.35 therefore, we have P(A)=0.40, P(B)=0.35, P(A’)=0.6, P(B’)=0.65, P(A and B)=0 Describe them in the table A A’ total B 0.35 B’ 0.65 total 0.40 0.60 1 Fill up the table A A’ total B 0.35 0.35 B’ 0.40 0.25 0.65 total 0.40 0.60 1 So, P(A’ and B)=0.35 P(A’ or B’)=P(A’)+P(B’)-P(A’ and B’)=0.6+0.65-0.25=1...
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Quiz 3 Solution - i.e p(B)=0.35 therefore we have P(A)=0.40...

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