Lecture 3 PES Su 2011 annotated

# Lecture 3 PES Su 2011 annotated - ME 200 Thermodynamics I...

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Unformatted text preview: ME 200: Thermodynamics I Lecture 3: Temperature, T, and Problem solving structure Prof. Sojka Summer 2011 In this Lecture … • Temperature • Problem Solving structure 2 3 Temperature • Zero th Law of Thermodynamics – When two objects are in thermal equilibrium with a third object, they are in thermal equilibrium with one another. • Properties of many substances change with temperature. 4 Temperature Scales Scale Kelvin (SI) Rankine (English) Relationship Absolute K ºR ºR = 1.8 x K Practical ºC ºF ºF = 1.8 x ºC + 32 K = ºC + 273.15 ºR = ºF + 459.67 5 Temperature Scales • Δ T ºR = Δ T ºF = 1.8 x ( Δ T K = Δ T ºC ) • USE ABSOLUTE TEMPERATURES IN ALL YOUR PROBLEM SOLUTIONS. 6 Solving Engineering Problems • Previous problems you encountered have been fairly straightforward. • The system was easy to define (only one type). • There were few basic equations . • You did not need to make assumptions . 7 Solving Engineering Problems ME 200 problems are not so straightforward. • Three types of systems. • Lots of basic equations. • You now need to make assumptions . 8 Problem Solution Methodology Important steps to solve any problem in a systematic...
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Lecture 3 PES Su 2011 annotated - ME 200 Thermodynamics I...

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