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ese271-1

# ese271-1 - A{f‘ “ta?” ESE 271 First Exam Name Spring...

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Unformatted text preview: A {f‘, “ta?” ESE 271 First; Exam Name: Spring, 2011 ID Number: Do not place your answers on this ("rout pugtn Each problem is worth 25 points" "5 Prob. I: Prob. 2: Prob. 3: Prob. 4: Prob. 1: Do a nodal analysis to get three cqunions that de Lennme the node vol rs in matrix form 1 Write your answe )y ﬁning in the {0H Célgt‘s m, ('3. and 13 owing matrix equation Assunw :sz4 virtual—short virtual‘open model for the op-amp. / IL I max/W“ \~ 1" ~'« JL ’ 2 4. 5m, + .L _ «I, ‘* A 7’7‘ 777 r. 6 ‘ 2 ' 3 a; 5‘ ‘r2 6 O ’U’f] 2 O km at v .4 dc: ’ ° 45-14 “’2 -0 (“PP”) + ‘T‘ ‘ ’/2 4: KCL at v node: 2 1/1 + 412-43 0 (power) j/z ‘ Prob. 2: Using a nodal analysis, find the nude Volta.ng m and v2, and then determine, the pom-2' dissipated in the 1/4 0 resistor. 3:! {Ow/{(5} ,qg ﬁfl’tA/thf VOArﬂ For I. BaLLauﬂ ARowvo 7’ 5:,“ rue BALLooMf . —'—" : ’V' «4-1/2=212 :2 )1 7 \$0) "I. :54);- kcl ON ‘rllf Bauaow' 1; “'1’? + V’W’ + 15 ~0 ' + y ' '/ 4 9 2 5‘9} 412 : 2 ‘4’!”- 7,5141" 4/" : \$4,; .7 ’0 VOJY“ 2 - 3 — 4/- .L. — J - z : 25‘6 wall: Paw'r 1'» 7:41. res/:far — N 9 “ (' 4,2) I ‘ (v 2) y 4 Prob. 3: Using the mesh curre Hts Show“ analysis. (In a mesh mmiysis to find thv uwxh (‘un‘eut 133‘ Ar D£D£IJDENT “V”; " RV]. Anauuo ournoa Loop: ~ I' :— -2+—;-l,+;12"0 . t} _ ,l' 42:53-21, :8-2('{)‘6 3 Prob. 4: Find the input resistance Rm 2 110/211). Do this by assuming a 1 ampere source (:(‘nUIecEud to the nodes 3 and b. 1 .JL; a 0.51:4; A Nan/u Avnvy v V, 9 IA 9 II “It :0 If 81 34’;“’=4 779% 3vo-2va :45 :4 / 1*- #E~(E/ Rt": 7‘- 9‘1). NALYJ'IJ‘,’ ANomm rum-mu Lama. A New A ‘ ~' :0 2(i -1) + 5H + “O ’I) I ...
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ese271-1 - A{f‘ “ta?” ESE 271 First Exam Name Spring...

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