Dolbier HW Solutions 243

Dolbier HW Solutions 243 - 237 CONJUGATION IN ALKADIENES...

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10.18 ( a ) ( b ) ( c ) ( d ) ( e ) ( f ) ( g ) ( h ) 10.19 ( a ) Since the product is 2,3-dimethylbutane we know that the carbon skeleton of the starting ma- terial must be Since 2,3-dimethylbutane is C 6 H 14 and the starting material is C 6 H 10 , two molecules of H 2 must have been taken up and the starting material must have two double bonds. The starting material can only be 2,3-dimethyl-1,3-butadiene. H 2 C C CH 3 CH 2 C 1 CH 3 2H 2 (CH 3 ) 2 CHCH(CH 3 ) 2 Pt C C C C C C ( E )-3-Ethyl-4-methyl-1,3-hexadiene CC CH 3 CH 2 H 3 C CH 2 CH 3 CH CH 2 (1 E ,5 E ,9 E )-1,5,9-Cyclododecatriene
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This note was uploaded on 09/26/2011 for the course CHM 2210 taught by Professor Reynolds during the Fall '01 term at University of Florida.

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