6physHW16

# 6physHW16 - The current in the 13.8-9 resistor in the...

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Unformatted text preview: The current in the 13.8-9 resistor in the Engine below is 0.775 A. Find the current in the other resistors in the circuit. Picture the Problem: Six resistors are connected to a battery in the manner indicated in the diagram. Strategy: The current i, through the 13.8-(2 resistor determines the voltage AVA“ because of Ohm’s Law. That potential difference can then be used to ﬁnd 12 and if.I , and the current 1' is the sum ofthe other three currents. Solution: 1. (it) Find AV“ using ()hm‘s Law: Ail-3‘H = 1', R1 ={0.775 A )(l3.8 Q)=10.7 l“ . 2. Apply Ohm‘s Law to R. in ﬁnd i4: 14 =9—é"—= ‘0 7 V = 0.622 A R, I72 (1 l" . 3.Apply Ohm's Law to F:~ and Rh to ﬁnd 12: L = A “‘9 2—ﬂ = 0.852 A ' * R5+Rh 8.45+4.1Io 4. Add the currents to ﬁnd l'I : r" = l". + I, + £4 = 0.852 +0.??5+ 0.622 A = 1248 A Insight: Ohm’s Law is a powerful tool for analyzing circuits because it applies to the entire circuit as a whole as well as to each individual element in the circuit. ...
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