03prob_11

# 03prob_11 - Assignment#3 Page 1 of 2 UC Davis Box ￼ 1 Box...

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Unformatted text preview: Assignment #3, 4/15/11 Page 1 of 2 UC Davis Box ￼ 1: Box ￼ 2: girl: F N1s F N2s F Ngs F 1e F 2e F ge F T1r F F f ge F T2r F √ 1 R √ F √ 2 =R √-F √ 1 135° Box ￼ 1: Box ￼ 2: girl: F N1s F N2s F Ngs F 1e F 2e F ge F T1r F F F T2r F √ 1 R √ F √ 2 =R √-F √ 1 135° Physics 9A-C Assignment #3 Cole [4.4]   F x  = F  cos oe is the angle that the rope makes with the ramp (oe = 30° in this problem), so   F x = F cos θ  õ  F = F x cos θ = 60 N cos 30 °  = 69.3 N  b)  F y  = F  sinoe =  F x   tan oe = 34.6 N. [4.16]  With  vø  = 0,   v 2 = v 2 + 2 a Δ x  õ   a = v 2 2 Δ x = 3 × 10 6 m ( ) 2 2 1.8 × 10 − 2 m ( )  = 2.50 ª 10 14  m/s 2 b)  v = vø + at õ    t = v t = 3 × 10 6 m/s 2.5 × 10 14 m/s 2  = 1.20 ª 10-2  s This time is also the distance divided by  the average speed.  c)   F = ma  = (9.11 ª 10-31  kg) (2.50 ª 10 14  m/s 2 ) = 2.28 ª 10-16  N. [4.34]  a)  v = 0  where  v 2 = v 2 − 2 a Δ x , and  v = vø -at.   Solving for  t:    t = v a = 2 Δ x v = 2 0.13 m ( ) 350 m/s   = 7.43 ª 10-4  s where  a = v 2 2 Δ x .  b)  F = ma  =  m v 2 2 Δ x =  1.8 × 10 − 3 kg ( ) 350 m/s ( ) 2 2 0.13 m ( ) ⎛ ⎝ ⎜ ⎞ ⎠ ⎟  = 848 N    Using  a = Δ v t  gives the same result....
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## This note was uploaded on 09/28/2011 for the course PHY 9A taught by Professor Svoboda during the Spring '08 term at UC Davis.

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03prob_11 - Assignment#3 Page 1 of 2 UC Davis Box ￼ 1 Box...

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