09quiz_11

# 09quiz_11 - Physics 9A-C Quiz week#9 Name ID(last 4 . . 1 1 cm= m 2 = m 2.

This preview shows page 1. Sign up to view the full content.

Physics 9A-C Quiz week #9 Name: 5/27/2011 ID(last 4): A meter stick with a mass of 0.160 kg is pivoted about one end so it can rotate without friction  about a horizontal axis.  The moment of inertia for a stick rotated about the center of mass is   Â cm =  1 12 m 2 and the moment about the end is Â p =  1 3 m 2 .  The meter stick is held in a  horizontal position and released.  As it swings through the vertical, calculate:   a) ( 3 pts) the change in gravitational potential energy of the stick;   Gravity acts at the center of mass.  The work done by gravity is - Î U cm . The potenial energy of  the meter stick will be least when it is vertical, at which point, the center of mass will have  lowered by 0.5 m  õ
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 09/28/2011 for the course PHY 9A taught by Professor Svoboda during the Spring '08 term at UC Davis.

Ask a homework question - tutors are online