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1443 Lecture 4

# 1443 Lecture 4 - 1443 Lecture 4 GRAPHICAL ANALYSIS x = x 0...

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1443 Lecture 4 GRAPHICAL ANALYSIS 1) Position Graph w/ No Acceleration (a=0) vt x x + = 0 {if a = 0 , v =v 0 } Intercept slope 2) Position Graph w/ Constant Acceleration 2 0 0 2 1 at t v x x + + = (Parabola) 3) Velocity Graph w/ Constant Acceleration Intercept slope

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Example: 1) What is x at t=4? x(4s)=9m 2) What is v between 2s and 8s? s m s m m s s s x s x t x v / 33 . 0 6 8 10 2 8 ) 2 ( ) 8 ( = - = - - = = 3) What is v at t=1s? ) 2 0 ( ) 1 ( s t s v s v = s m s m m s s s x s x t x v / 0 . 4 2 0 8 0 2 ) 0 ( ) 2 ( = - = - - = = 4) What is v at t=8s? v =0 5) What is a at t=4s? a=0 Some problems are much easier to solve graphically Example : A hockey player passes the puck. After uniform deceleration; the puck comes to rest 200m away. How far does it travel in half this time? Vectors (2-dimensional) A “Vector” quantity is characterized by two properties: Magnitude and Direction (2 numbers) A “Scalar” quantity is characterized by a single property: Magnitude (1 number) 9 . 36 ) 00 . 5 ( = = m V V θ
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1443 Lecture 4 - 1443 Lecture 4 GRAPHICAL ANALYSIS x = x 0...

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