1443 Lecture 5

1443 Lecture 5 - 1443 Lecture 5 Example 5 : Vector has a...

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Unformatted text preview: 1443 Lecture 5 Example 5 : Vector has a magnitude of 12.3km and point due west. Vector points due north. a) What is the magnitude of if B A + has a magnitude of 15.0km? b) What is the direction of B A + relative to due west? c) What is the magnitude of B if B A - has a magnitude of 15.0 km? d) What is the direction of B A - relative to due west? a) km km A C B C B A B A C 6 . 8 ) 3 . 12 ( (15.0km) 2 2 2 2 2 2 2 =- =- = = + + = b) 9 . 34 . 15 3 . 12 1 1 = = =-- km km Cos C A Cos θ North of West c) km B C B A B A C 6 . 8 2 2 2 = = +- = d) 9 . 34 1 = =- C A Cos θ South of West Example 6 : Find the resultant of 3 displacement vectors by means of the component method = 5.00m ∠ 160 ° = 5.00m ∠ 60 ° = 4.00m ∠ 270 ° A x = (5.00m)Cos(160 ° ) = – 4.70m A y = (5.00m)Sin(160 ° ) = 1.71m B x = (5.00m)Cos(60 ° ) = 2.50m B y = (5.00m)Sin(60 ° ) = 4.33m C x = (4.00m)Cos(270 ° ) = 0.00m C y = (4.00m)Sin(270 ° ) = – 4.00m R x = A x + B x + C x = – 4.70m + 2.50m + 0.00m = – 2.20m R...
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This note was uploaded on 09/27/2011 for the course PHYS 1443 taught by Professor Spurlock during the Fall '08 term at UT Arlington.

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1443 Lecture 5 - 1443 Lecture 5 Example 5 : Vector has a...

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