Key Quiz 12 09-106 S 11 - (2 points) Cl 2 + 2e- 2Cl-E =...

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Name ______________________________ _ Quiz 12 (10 points) 09-106 Spring 2011 Recitation ( CIRCLE ONE TA and ONE TIME ): Christian Steve Brendan 6:30 7:30 4/28/11 (10 minutes allowed) Ag (s) Ag + (aq) Fe (s) Fe 3+ (aq) In order to ensure the maximum amount of partial credit on short problems, please show all work and clearly circle your final answers. A listing of constants and equations are on the reverse side. 1. For the electrolytic cell under standard conditions illustrated on the right: (a) Write the overall cell reaction. [The standard electrode reduction potentials are: 0.80 V for Ag + |Ag(s) - 0.04 V for Fe 3+ |Fe(s) ] (4 points) (b) Which metal makes up the cathode? Ag Fe ( circle one ) (1 point) (c) Calculate the standard state cell voltage. (2 points) 2. Given the following standard potentials, circle below the best reducing agent,
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Unformatted text preview: (2 points) Cl 2 + 2e- 2Cl-E = 1.36 V Mg 2+ + 2e- Mg E = -2.37 V 2H + + 2e- H 2 E = 0.00 V Cl 2 Cl-H 2 Mg Mg 2+ 3. A solution at 298 K contains 1.0 M of each of Cd 2+ , Ag + , Au 3+ , and Ni 2+ in the cathode compartment of an electrolytic cell. Circle below the metal that plates out (forms) last as the voltage is gradually increased. Cd Ag Au Ni (1 point) Current (amp) or potential (volt) Name ______________________________ _ Quiz 12 (10 points) 09-106 Spring 2011 Recitation ( CIRCLE ONE TA and ONE TIME ): Christian Steve Brendan 6:30 7:30 4/28/11 (10 minutes allowed) I = Q /t 1 A = 1 C/s F = 96,485 C/ mol e- G = -nF E 1 V = 1 J/C G = -RT ln K ( R = 8.31 Jmol-1 K-1 )...
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Key Quiz 12 09-106 S 11 - (2 points) Cl 2 + 2e- 2Cl-E =...

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