ALCOHOLS, DIOLS, AND THIOLS395The structure cannot be correct. It would exhibit only two peaks in its 13C NMRspectrum, because the two terminal carbons are equivalent to each other.15.46The observation of a peak at m/z31 in the mass spectrum of the compound suggests the presence ofa primary alcohol. This fragment is most likely . On the basis of this fact and theappearance of four different carbons in the 13C NMR spectrum, the compound is 2-ethyl-1-butanol.15.47–15.49Solutions to molecular modeling exercises are not provided in this Study Guide and Solutions Man-ual.You should use Learning By Modelingfor these exercises.SELF-TESTPART AA-1.For each of the following reactions give the structure of the missing reactant or reagent.
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