unsaturation. The highest feld peak in the NMR spectrum is a 3-proton triplet, corresponding to themethyl group of a CH3CH2unit. The 2-proton signal at d3.0 ppm corresponds to a CH2unit adja-cent to the carbonyl group and, because it is a triplet, suggests the grouping CH2CH2C?O. Thecompound is butyl phenyl ketone (1-phenyl-1-pentanone).17.47With a molecular formula of C7H14O, the compound has an index of hydrogen defciency of 1. Weare told that it is a ketone, so it has no rings or double bonds other than the one belonging to itsC?O group. The peak at 211 ppm in the 13C NMR spectrum corresponds to the carbonyl carbon.Only three other signals occur in the spectrum, and so there are only three types of carbons otherthan the carbonyl carbon. This suggests that the compound is the symmetrical ketone 4-heptanone.17.48Compounds A and B are isomers and have an index of hydrogen defciency of 5. Signals in theregion 125–140 ppm in their13
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This note was uploaded on 09/28/2011 for the course CHM 2210 taught by Professor Reynolds during the Fall '01 term at University of Florida.