Dolbier HW Solutions 368

Dolbier HW Solutions 368 - 462 ALDEHYDES AND KETONES:...

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unsaturation. The highest f eld peak in the NMR spectrum is a 3-proton triplet, corresponding to the methyl group of a CH 3 CH 2 unit. The 2-proton signal at d 3.0 ppm corresponds to a CH 2 unit adja- cent to the carbonyl group and, because it is a triplet, suggests the grouping CH 2 CH 2 C ? O. The compound is butyl phenyl ketone (1-phenyl-1-pentanone). 17.47 With a molecular formula of C 7 H 14 O, the compound has an index of hydrogen de f ciency of 1. We are told that it is a ketone, so it has no rings or double bonds other than the one belonging to its C ? O group. The peak at 211 ppm in the 13 C NMR spectrum corresponds to the carbonyl carbon. Only three other signals occur in the spectrum, and so there are only three types of carbons other than the carbonyl carbon. This suggests that the compound is the symmetrical ketone 4-heptanone. 17.48 Compounds A and B are isomers and have an index of hydrogen de f ciency of 5. Signals in the region 125 140 ppm in their 13
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This note was uploaded on 09/28/2011 for the course CHM 2210 taught by Professor Reynolds during the Fall '01 term at University of Florida.

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