{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# General Physics I Answers - huynh(hph268 HW#1 clark(56485...

This preview shows pages 1–3. Sign up to view the full content.

huynh (hph268) – HW #1 – clark – (56485) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points Consider the expression 2 π r g , where is length and g is gravitational acceleration in units oF length divided by time squared. Evaluate its units. 1. s correct 2. m 3. s m 4. m 2 5. m s 6. s 2 7. p m s P 2 8. p s m P 2 Explanation: [ ] = m and [ g ] = m s 2 . 2 and π are constants, so r [ ] [ g ] = R m ÷ m s 2 = R m · s 2 m = s 2 = s . 002 10.0 points A graph oF a straight line going through two points is shown below. b b y - 5 - 3 - 1 0 1 2 3 4 5 x - 5 - 4 - 3 - 2 - 1 0 1 2 3 4 5 What is the equation oF this line? 1. y = + 2 9 x + 8 9 2. y = - 9 2 x + 8 9 3. y = - 2 9 x + 4 4. y = - 9 2 x - 8 9 5. y = + 2 9 x + 4 6. y = + 2 9 x - 8 9 correct 7. y = + 9 2 x - 4 8. y = - 2 9 x - 8 9 9. y = + 2 9 x - 4 10. y = + 9 2 x - 8 9 Explanation: Let : ( x 1 , y 1 ) = ( - 5 , - 2) ( x 2 , y 2 ) = (4 , 0) . The slope is m = (0) - ( - 2) (4) - ( - 5) = + 2 9 . Using 2 points ( y - y 1 ) = m ( x - x 1 )

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
huynh (hph268) – HW #1 – clark – (56485) 2 y = m ( x - x 1 ) + y 1 , so y = + 2 9 ( x + 5) - 2 = + 2 9 x - 8 9 . 003 (part 1 of 2) 10.0 points Consider two planets with uniform mass dis- tributions. The mass density and the radius of planet 1 are ρ 1 and R 1 , respectively, and those of planet 2 are ρ 2 and R 2 What is the ratio M 1 M 2 of their masses? 1. M 1 M 2 = p ρ 1 ρ 2 Pp R 1 R 2 P 3 correct 2. M 1 M 2 = p ρ 1 ρ 2 R 2 R 1 P 3 3. M 1 M 2 = p ρ 2 ρ 1 R 1 R 2 P 4. M 1 M 2 = p ρ 2 ρ 1 R 1 R 2 P 2 5. M 1 M 2 = p ρ 2 ρ 1 R 1 R 2 P 3 6. M 1 M 2 = p ρ 2 ρ 1 R 2 R 1 P 3 7. M 1 M 2 = p ρ 1 ρ 2 R 1 R 2 P 2 8. M 1 M 2 = p ρ 1 ρ 2 R 2 R 1 P 2 9. M 1 M 2 = p ρ 2 ρ 1 R 2 R 1 P 2 10. M 1 M 2 = p ρ 1 ρ 2 R 1 R 2 P Explanation: ρ = m V , so M 1 M 2 = ρ 1 p 4 3 π R 3 1 P ρ 2 p 4 3 π R 3 2 P = ρ 1 R 3 1 ρ 2 R 3 2 . 004 (part 2 of 2) 10.0 points What is the ratio A 1 A 2 of the circular areas deFned by the two equators? 1. A 1 A 2 = p R 2 R 1 P 2 2. A 1 A 2 = π p R 1 R 2 P 3 3. A 1 A 2 = π p R 1 R 2 P 2 4. A 1 A 2 = p R 1 R 2 P 3 5.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 6

General Physics I Answers - huynh(hph268 HW#1 clark(56485...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online