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Unformatted text preview: V out = 0 K * s / s + s4 = V O V S = V O V S = As s infinity K = (R C  R L ) / r e As s We can solve circuit for s 6 6 Method of ShortCircuit Time Constants We do not need to solve for the poles & zeros. Our objective is to select, C in , C out & C E to obtain a desired frequency response usually characterized by the low halfpower frequency. Bode Plot 7 The Amplifier Transfer Function A (s) = V O (s) V i (s) DC Amplifier Capacitively Coupled Amplifier 8 ω L Lower Half  Power Frequency ω L = 2 π f L Can be estimated using Method Of Short  Circuit Time Constants ω H Upper Half  Power Frequency ω H = 2 π f H Can be estimated using Method Of Open Circuit Time Constants Gray & Searle “Electronic Principles” John Wiley 1969...
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 Spring '09
 Amplifier, Frequency, Capacitively Coupled Amplifier

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