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**Unformatted text preview: **V out = 0 K * s / s + s4 = V O V S = V O V S = As s infinity K = (R C || R L ) / r e As s We can solve circuit for s 6 6 Method of Short-Circuit Time Constants We do not need to solve for the poles & zeros. Our objective is to select, C in , C out & C E to obtain a desired frequency response usually characterized by the low half-power frequency. Bode Plot 7 The Amplifier Transfer Function A (s) = V O (s) V i (s) DC Amplifier Capacitively Coupled Amplifier 8 L Lower Half - Power Frequency L = 2 f L Can be estimated using Method Of Short - Circuit Time Constants H Upper Half - Power Frequency H = 2 f H Can be estimated using Method Of Open Circuit Time Constants Gray & Searle Electronic Principles John Wiley 1969...

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