5.9.3 Part II Low Frequency Response - Short Circuit Time Constants L4_2

5.9.3 Part II Low Frequency Response - Short Circuit Time Constants L4_2

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5.9.3 Part II The Method Of Short Circuit Time Constants Lecture 4 Part II Wed. Jan. 20, 2010
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2 Consider the low-frequency equivalent circuit of an electronic circuit with 3 Coupling and/or Bypass Capacitors: C 1 , C 2 , C 3 Low Frequency Equivalent Circuit Purely Resistive All Independent Sources Are Dead Network Inside Box Is Purely Resistive I 1 = g 11 V 1 + g 12 V 2 + g 13 V 3 I 2 = g 21 V 1 + g 22 V 2 + g 23 V 3 I 3 = g 31 V 1 + g 32 V 2 + g 33 V 3 1 / R 1S = g 11 = I 1 / V 1 with V 2 3 = 0 g 11 = Input Conductance with V 2 3 shorted 1 / R 2S = g 22 = I 2 / V 2 with V 1 3 = 0 g 22 = Input Conductance with V 1 3 shorted 1 / R 3S = g 33 = I 3 / V 3 with V 1 2 = 0 g 33 = Input Conductance with V 1 2 shorted
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3 To determine g 11 Remove C 1 and short out C 2 3 and calculate the conductance ratio I 1 / V 1 To determine g 22 Remove C 2 and short out C 1 3 and calculate the conductance ratio I 2 / V 2 To determine g 33 Remove C 3 and short out C 1 2 and calculate the conductance ratio I 3 / V 3 Low Frequency Circuit Including C 1 , C 2 3 I 1 ’ = (g 11 + sC 1 )V 1 + g 12 V 2 + g 13 V 3 I
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5.9.3 Part II Low Frequency Response - Short Circuit Time Constants L4_2

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