CSCCCECC Capacitor Selection Lecture 19_1

CSCCCECC Capacitor Selection Lecture 19_1 - EE 311 Lecture...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Zubair Rehman EE 311 Lecture 19 & EEO 311 Lecture 18 Monday Feb. 22, 2010 CS-CC-CE-CC Capacitor Selection
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
2
Background image of page 2
3 Selection of C IN , C OUT E2 for f L = 50 Hz f L = ω L / 2 π = 1 / 2 π C IN R 1S + 1 / 2 π C OUT R 2S + 1 / 2 π C E2 R 3S 5 Hz 5 Hz 40 Hz 1 / 2 π C IN R 1S = 5 Hz or C IN = 1 / (2 π * 5 Hz * R 1S ) R 1S = R S + R1 || R INJ1 R INJ1 >> R1 R 1S = R S + R1 = 50 + 200 k ≈ 0.2 Meg F F eg C IN μ π 16 . 0 2 1 10 1 = = Μ 0.2 =
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
4 Selection of C IN , C OUT E2 for f L = 50 Hz f L = ω L / 2 π = 1 / 2 π C IN R 1S + 1 / 2 π C OUT R 2S + 1 / 2 π C E2 R 3S 5 Hz 5 Hz 40 Hz 1 / 2 π C OUT R 2S = 5 Hz or C OUT = 1 / (2 π * 5 Hz * R 2S ) R 2S = R L + R 6 || R OUTQ3 Since Q3 is a CC Stage (r x3 o3 = infinity) R OUTQ3 = [(r π3 + r x3 + R 5 || R OUTQ2 ) / ( β 3 +1)] = [(r π3 + R 5 || r o2 ) / ( β 3 +1)] r π3 = ( β 3 +1) * r e3 = ( β 3 +1) * (V T / I E3 ) o2 = infinity C OUT = 1 / (10 π * 0.1 k) = 1mF / π = 0.3 mF = 300 μ F + = + + = + + = + + + = + + + + = 3
Background image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 9

CSCCCECC Capacitor Selection Lecture 19_1 - EE 311 Lecture...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online