CSCCCECC Design_1_1

# CSCCCECC Design_1_1 - EE311& EE311Lecture18Part2...

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Design of CS-CC-CE-CC Multistage Amplifier Zubair Rehman  EE 311 Lecture 18 Part 2 Friday Feb. 19, 2010

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3 R L 100 (more difficult) minA V 1000 (more difficult) R IN > 200 k (no change) R OUT < 100 Ω (more difficult) V PP > V CC / 2 = 20V/2 = 10V I CQ3 = 132 mA [For h FE = 100, I B ≈ 1 mA) V CEQ3 = 6.7 V P D = I CQ3 V CEQ3 = 132 mA * 6.7 V = 884 mW = 0.884 W Allow Safety Factor x2 P DMAX = 1.8 W Choose R E4 = R L V CEQ3 = (1/3)*V CC I EQ3 R E4 = (2/3)*V CC = (2/3)*20V=13.3V I EQ3 = 13.3V/ R E4 = 13.3V/0.1k = 133 mA

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4 Observations 1. 2. 3. Last Stage I EQ3 = 133 mA 4. Next To Last Stage Reduce I CQ2 To I CQ2 = 25 mA 5. Stage 2 Reduce I CQ1 To I CQ1 = 5 mA 6. Stage 1 Select I D1 7. V PPQ3 = 2 * 6.5V = 13 V 8. V PPQ2 = 13 V also because Q3 has A V = 1 9. V PPQ1 = 13V/100 = 0.13V because Q2 has A V = 100 10. V PPJ1 = 0.13 V = 130 mV also because Q1 has A V = 1 11. At J1 Input V INPP = 130mV/10 =13 mV because J1 has A V = 10
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CSCCCECC Design_1_1 - EE311& EE311Lecture18Part2...

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