L6-1 5.9.3 CE Low Frequency Response Excercises - 5.52, P5.163, P5.164, P5.161 L5_1

L6-1 5.9.3 CE Low Frequency Response Excercises - 5.52, P5.163, P5.164, P5.161 L5_1

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 5.9 Low Frequency Response of CE Lecture 6 Friday Jan. 22, 2010 Zubair Rehman 2 Exercise 5.52 A common-emitter amplifier has C C1 = C C2 = C E = 1 F, R B = 100 k , R sig = 5 k , g m = 40 mA/V, r = 2.5 k, R C = 8 k and R L = 5 k. = 40m *2.5k = 100 Assuming that the three capacitors do not interact. Find f P1 , f P2 , and f P2 and estimate f L . Figure 5.71 a 3 Exercise 5.52 Solution Hz f s rad ms F k C R k k k k k k r R R R F P P C S P B sig S 4 . 21 2 / 134 44 . 7 1 1 * 44 . 7 1 1 44 . 7 44 . 2 5 5 . 2 || 100 5 ) || ( 1 1 1 1 1 1 = = = = = = = + = + = + = = = 1 C C1 C1 f L = f P1 + f P2 + f P3 = 21.4 + 2210 + 12.2 = 2244 Hz = 2.24 kHz kHz f s krad s C R s F C R k k k R R r R F P P s P S sig B S 21 . 2 2 / / 91 . 13 9 . 71 1 2 1 9 . 71 1 * 9 . 71 2 9 . 71 101 26 . 7 1 100 100 5 . 2 || 2 2 2 2 2 2 = = = = = = = = = + + = 1 + + = = = 1 C C2 E Hz f s rad ms C R ms F k C R k k k R R R F C C P P C S P C S C L S C 2 . 12...
View Full Document

Page1 / 9

L6-1 5.9.3 CE Low Frequency Response Excercises - 5.52, P5.163, P5.164, P5.161 L5_1

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online