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# tutorial10 - CS 230 Tutorial 10 Jonathan Rodriguez...

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CS 230 Tutorial 10 March 21, 2011 Jonathan Rodriguez [email protected]

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Tutorial 10 Parsing Revisited Assignment 4 Sample Solutions
Parsing 20 - 5 / 3 INTEGER “20” INTEGER “3” MINUS DIV INTEGER “5”

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Leftmost Derivation Scans input from left to right LL(k): Leftmost Linear with k tokens look-ahead LL(1): Simplest form: 1 token look-ahead Derivation can be done with a Recursive Descent Parser, which does top-down parsing
LL(1) Grammar expression : term moreexpr moreexpr : PLUS term moreexpr | MINUS term moreexpr | ε term : INTEGER moreterm moreterm : MULT INTEGER moreterm | DIV INTEGER moreterm | ε

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A More Compact Grammar expression : term { (PLUS | MINUS) term } term : INTEGER { (MULT | DIV) INTEGER } Braces mean zero or more
Parser Code function term(): accept(INTEGER) while next token is MULT or DIV: accept(MULT or DIV) accept(INTEGER) function expression(): term() while next token is PLUS or MINUS: accept(PLUS or MINUS) term() Accepts the next token from the input stream (must be of given type)

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Derivation Steps 1. <expression>
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tutorial10 - CS 230 Tutorial 10 Jonathan Rodriguez...

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