Homework_TN4_sol

Homework_TN4_sol - For parts the following learning was...

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Homework – Technical Note 4 1. Since b=0.9 Y(100)=0.9* Y (50)= 0.18 hours Y(200)=0.9 *Y (100)=0.162 hours Y(400)=0.9 *Y (200)=0.1458 hours Note: We can compute the general formula as follows: First we compute n = ln(b)/ln(2) = ln(0.9)/ln(2) = -0.152 We also know that Y (50) = 0.2 0.2= K(50) -0.152 K=0.36 So, Y(x) = 0.36x -0.152 2. For labor the following learning was experienced: Unit 1 to 2 = 1500/2000 = 75%, so b = 0.75, n = ln(b)/ln(2) = -0.415 and K = 2000. Labor for the third unit: Y(3) = 2000(3) -0.415 = 1267 Labor for the fourth unit: Y(4) = 2000(4) -0.415 = 1125 Total labor hours = 2000 + 1500 + 1267 + 1125 = 5892 hours
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Unformatted text preview: For parts, the following learning was experienced: Unit 1 to 2 = 37050/39000 = 95%, b = 0.95, n = ln(b)/ln(2) = -0.074 and K = 39000. Parts cost for the third unit: Y(3) = 39000(3)-0.074 = 35955 Parts cost for the fourth unit: Y(4) = 39000(4)-0.074 = 35198 Total parts cost = 39000 + 37050 + 35955 + 35198 = \$147203 3. a. Units 1 to 2 = 640/970 = 65.98% Units 2 to 4 = 380/640 = 59.37% Units 4 to 8 = 207/380 = 54.47% Average learning rate = 59.94% Round this to 60%. b. b = 0.6, so n = ln(b)/ln(2) = -0.737. K = 970, so Y(x) = 970 x-0.737 and Y(1000) = 5.96 hours...
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This note was uploaded on 09/29/2011 for the course MGT 3501 taught by Professor Chang during the Fall '10 term at Georgia Tech.

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