Problem Set 5 Q. 4 Answer

Problem Set 5 Q. 4 Answer - deletion in the second codon...

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Problem set 5, Q. 4 (also Problem set 6, Q. 1) Answer 4 . A comparison of the amino acid sequences provided for the wild type and the pseudo-wild revertant shows that amino acids 1, 6 and 7 are the same in both cases. Amino acids 2, 3, 4 and 5 have been changed. Alteration of multiple amino acids suggests 2 frameshift mutations- one between a.a. 1 and 2 and a second mutation between a.a. 5 and 6. These two mutations must be of opposite signs so that they compensate for each other (one is a deletion and the other is an addition). There was a
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Unformatted text preview: deletion in the second codon (UUC-> UC). This changed the reading frame from the 2 nd codon to the end of the protein resulting in a defective protein. The second mutation was an addition of a nucleotide at the end of the 5th codon (GUG AUU ->either GU N GAU or GUG G AU). This restored the reading frame so that the protein was normal after the 5th amino acid. From the data it cannot be determined whether the deletion (-U ) or the addition ( +N or +G ) occurred first (see next page for details)-...
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This note was uploaded on 09/29/2011 for the course GENETICS 380 taught by Professor Glodowski during the Spring '08 term at Rutgers.

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