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Unformatted text preview: Sample B 49.15 g Sample B submerged 42.9 g Sample B in Unknown 44.4 g Hydrometer Unknown Liquid 825 Water 1 Mass of unkown liquid 42.6g Mass of Beaker 83.8 g Mass of water 437.9 g Mass of water with finger 444.7 g Calculations Buoyant Force Fb= p Vg= W (air) x W(water) = (444.7) / (444.7-437.9) = 65.40 Questions 1. Water level of the pool will be lower because the buoyant force in the the boat is greater than the volume of the scrap iron 2. The iron will not be in the pool, which means it will be lower 3. 4. The wooden block will be the same as the weight of the wooden block 5. A) The ice will become lower because the increment in the size B.) The ice cube was pulled down so it will be lower C.) The ice cube wasnt pulled that far down so it because higher Conclusion In this experiment I found out the specific gravity and the buoyant force by using the Sample Box A and Sample Box B by sinking in the water and the unknown liquid....
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