Quiz19Solutions - y 9 y = y = a(1 9 2 x 2 3 2 x 3 21 8 x 4...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Math 3323 - Fall 2009 Quiz #19 Answers ( Recall that y ( x ) =x is a solution to all of these, and so should appear as part of the general solution. ) Your Problem General Solution (1 ! x ) "" y + 2 x " y ! 2 y = 0 y = a 0 (1 + x 2 + 1 3 x 3 ! 1 15 x 5 + ! ) + a 1 x (1 ! x ) "" y + 3 x " y ! 3 y = 0 y = a 0 (1 + 3 2 x 2 + 1 2 x 3 ! 1 8 x 4 ! 9 40 x 5 + ! ) + a 1 x (1 ! x ) "" y + 4 x " y ! 4 y = 0 y = a 0 (1 + 2 x 2 + 2 3 x 3 ! 1 3 x 4 ! 7 15 x 5 + ! ) + a 1 x (1 ! x ) "" y + 6 x " y ! 6 y = 0 y = a 0 (1 + 3 x 2 + x 3 ! x 4 ! 6 5 x 5 + ! ) + a 1 x (1 ! x ) "" y + 7 x " y ! 7 y = 0 y = a 0 (1 + 7 2 x 2 + 7 6 x 3 ! 35 24 x 4 ! 203 120 x 5 + ! ) + a 1 x (1 ! x ) "" y + 8 x " y ! 8 y = 0 y = a 0 (1 + 4 x 2 + 4 3 x 3 ! 2 x 4 ! 34 15 x 5 + ! ) + a 1 x (1 ! x ) "" y + 9 x "
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: y ! 9 y = y = a (1 + 9 2 x 2 + 3 2 x 3 ! 21 8 x 4 ! 117 40 x 5 + ! ) + a 1 x (1 ! x ) "" y + 12 x " y ! 12 y = y = a (1 + 6 x 2 + 2 x 3 ! 5 x 4 ! 27 5 x 5 + ! ) + a 1 x...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern